Please explain the concept behind the question.
33. The current carrying wire and the rod AB are in the same plane. The rod moves parallel to the wire with a velocity v. Which one of the following statements is true about induced emf in the rod ?
(a) End A will be at lower potential with respect to B.
(b) A and B will be at the same potential
(c) There will be no induced emf in the rod
(d) Potential at A will be higher than that at B.
Dear Student,
Here we are using concept of Fleming's right hand rule.
Fleming’s Right Hand Rule is used to find the direction of the induced emf of a conductor moving in a magnetic field. This rule is also called the Generator rule. The thumb, the first and the second fingers on the right hand are held so that they are at right angles to each other. If the first finger points in the direction of the magnetic field and the thumb in the direction of the motion of the conductor then the second finger will point in the direction of the induced current in the conducted
According to Fleming's right hand rule Potential at A will be higher than that at B
option (d ) is correct
Regards
Here we are using concept of Fleming's right hand rule.
Fleming’s Right Hand Rule is used to find the direction of the induced emf of a conductor moving in a magnetic field. This rule is also called the Generator rule. The thumb, the first and the second fingers on the right hand are held so that they are at right angles to each other. If the first finger points in the direction of the magnetic field and the thumb in the direction of the motion of the conductor then the second finger will point in the direction of the induced current in the conducted
According to Fleming's right hand rule Potential at A will be higher than that at B
option (d ) is correct
Regards