please explain this one in simple way Share with your friends Share 0 Vipra Mishra answered this Dear Student Maxwell's generalisation of Ampere's circuital law is given as follows∮B→.dl→ =μoI+ID =μoI+εodϕdtConsider that a parallel capacitor C is charging in a circuit.The magnitude of electric field between the two plates will beE =qεoA and is perpendicular to the surface of the plate.φE = E→ . A→ =EA Cos 0 =qεoA×A= qεodφEdt = dqεodt dqdt =εodφEdtHere dqdt is rate of change of charge with timeI =εodφEdt Regards 0 View Full Answer Chirag Prasad answered this Nhi hoga merese 0 Alexendra Daddario answered this Leave it 0
