Please explain this question in detail Share with your friends Share 0 Animesh Paul answered this Dear student, The reactions are as follows- Na → Na+ + e- IE = 5.1 eV ----(i)Na+ + e- → NaAs we can see from the above reaction that the second reaction is inverse of the first reactio, therefore electron gain enthalpy of Na+ is reverse of ionization energy.∆Heg = - 5.1 eV Hence, the correct option is (B). Regards 1 View Full Answer