Please explain this sum breifly and also the formula because I am not able solve this sum.

Dear Student,

Please find below the solution to the asked query:

Given product of two numbers  =  324

First we make prime factors of 324 , As :

So,

324  =  2 $\times$ 2 $\times$ 3 $\times$ 3 $\times$ 3 $\times$ 3

And we know : H.C.F. stands for Highest common factor .

Now we form two numbers and their H.C.F. , As :

I ) 4 ( 2 $\times$ 2 )  and 81 ( 3 $\times$ 3 $\times$ 3 $\times$ 3 ) , So H.C.F. ( 4 and 81 ) =  1 

II ) 2  and 162 ( 2 $\times$ 3 $\times$ 3 $\times$ 3 $\times$ 3 ) , So H.C.F. ( 2 and 162 ) =  2

III ) 12 ( 2 $\times$ 2 $\times$ 3 )  and 27 ( 3 $\times$ 3 $\times$ 3 ) , So H.C.F. ( 12 and 27 ) =  3

IV ) 36 ( 2 $\times$ 2 $\times$ 3 $\times$ 3 )  and 9 ( 3 $\times$ 3 ) , So H.C.F. ( 36 and 9 ) =  3 $\times$ 3 = 9

V ) 108 ( 2 $\times$ 2 $\times$ 3 $\times$ 3  $\times$ 3 )  and  3 , So H.C.F. ( 108 and 3 ) =  3

Here, we can see that only HCF = 9 ( That we calculate in IV )  is matches with one of the given option .

Therefore,

Option ( B )                                                             ( Ans )


Hope this information will clear your doubts about topic.

If you have any more doubts just ask here on the forum and our experts will try to help you out as soon as possible.

Regards