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Solution
This equation well explained in studymaterial. Link is given below
https://www.meritnation.com/cbse-class-12-science/physics/physics-part-ii/dual-nature-of-radiation-and-matter/studymaterial/46_4_216_255_8794
 

Einstein’s Photoelectric Equation

• Einstein explained the various laws of photoelectric emission on the basis of Planck’s quantum theory. According to Planck’s quantum theory, light radiations consist of small packets of energy called quanta. One quantum of light radiation is called a photon, which travels with the speed of light. The energy of a photon is given by,

E = hν

Where,

h − Planck’s constant

ν − Frequency of light

• Consider a photon of light frequency ν incident on a photosensitive metal surface. The energy of the photon (= hν) can be used in two ways:

(i) To liberate the electron from the metal surface (= Work function)

(ii) The rest of the energy of the photon is used in imparting the maximum kinetic energy k_max to the emitted photoelectrons.
$h\nu ={\phi }_o +\frac{1}{2}m{v^2}_{max}$

Where,

Φ₀ − Work function of the metal

v_max − Maximum velocity of the emitted photoelectron
$k_{max} =\frac{1}{2}m{v^2}_{max} = h\nu -{\phi }_o$

Where,

k_max − Maximum kinetic energy of the photoelectrons

1. If ν<νo​, then the maximum kinetic energy is negative, which is impossible. Hence, photoelectric emission does not take place for the incident radiation below the threshold frequency. Thus, the photoelectric emission can take place if ν>νo​.
2. The maximum kinetic energy of emitted photoelectrons is directly proportional to the frequency of the incident radiation. This means that maximum kinetic energy of photoelectron depends only on the frequency of incident light.