Please find an answer

Dear student,

Ans- 5 According to the Rydberg equation,
$$\begin{gathered} \frac{1}{\mathrm{\lambda }} = 109678\left(\frac{1}{{{\mathrm{n}}_1}^2}-\frac{1}{{{\mathrm{n}}_2}^2}\right) \\ \mathrm{Here} {\mathrm{n}}_1 = 5, {\mathrm{n}}_2 = \infty \\ \mathrm{Therefore}, \\ \frac{1}{\mathrm{\lambda }}= 109678\left(\frac{1}{5^2}-\frac{1}{{\infty }^2}\right) \\ \frac{1}{\mathrm{\lambda }}= \frac{109678}{25} \\ \mathrm{or} \mathrm{\lambda } = 222.793\times {10}^{-6}\mathrm{m} \end{gathered}$$

Now,
Energy is given as,
$$\begin{gathered} \mathrm{E} = \frac{\mathrm{hc}}{\mathrm{\lambda }} \\ \mathrm{E} = \frac{6.63\times {10}^{-34}\times 3\times {10}^8}{227.93\times {10}^{-6}} = 0.08726\times {10}^{-20}\mathrm{J} \end{gathered}$$

For remaining queries, we request you to please post them in separate threads to have rapid assistance from our experts.

Regards