Please find the answer of question no.3 and 4
Dear student,
(3)

In triangle APC and AQB,
Angle A (common)
(3)

In triangle APC and AQB,
Angle A (common)
AB = AC ( given)
AP = AQ ( given)
by sas rule of congruency
Triangle APC congruent to triangle AQB
Therefore,
CP =BQ (by c.p.c.t)
And,
Angle APC = Angle AQB ( by c.p.c.t)
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Post the remaining questions in different thread so that our experts can help you with the solution.
Regards