Please find the value of trigonometric ratios of cos theta= 2m/m^2-1
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Q. cos θ = 2 m m 2 + 1

Hi, here in words cos is 2mm2-1and in expression cos is 2mm2+1 so for correct query lets take 2mm2+1cos θ=2mm2+1=basehypotenuseso altitude= hypotenuse2-base2=m2+12-2m2=m4+1+2m2-4m2=m2-12=m2-1so sinθ= altitudehypotenuse= m2-1m2+1tanθ=altitudebase=m2-12mand sec θ= 1cosθ= m2+12mcosec θ= 1sinθ=m2+1m2-1cot θ= 1tanθ= 2mm2-1

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