Please give answer fast

Dear Student,
P is (36,48).
M is on x axis and at the same horizontal distance as P, so M = (36,0)
Equation of line OP :
$$\begin{gathered} y = mx + c \\ m =\frac{48 - 0}{36 - 0} = \frac{4}{3} \\ OP passes through (0,0) \\ So, 0 = \frac{4}{3}\times 0 +c \\ c = 0 \\ OP is y = \frac{4}{3}x or 3y = 4x \\ So, AB is perpendicular to OP \\ m of AB\times \frac{4}{3} = -1 \\ m of AB = -\frac{3}{4} \\ so, y = -\frac{3}{4}x + a \\ Now, AB passes through (38,48) \\ So 48 = -\frac{3}{4}\times 36 + a \\ a = 48 + 27 = 75 \\ So, equation of AB is \\ y = -\frac{3}{4}x + 75 \\ 4y + 3x = 300 \\ Now, let A = (0,y) \\ 4y + 3\times 0 = 300 \\ y = 75 \\ A =(0,75) \\ let B = (x,0) \\ 4\times 0 + 3x = 300 \\ x = 100 \\ B = (100,0) \end{gathered}$$

Regards,