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Dear Student,
We have,an=m i.ea+n-1d=m ---(1)and,am=ni.ea+m-1d=n---(2)Subtracting (2) from (1),we get;n-1d-m-1d=m-nn-1-m+1d=m-nn-md=m-n-m-nd=m-nd=-1,now, substituting d=-1 in eqn (1), we get;a+(n-1)×-1=ma-n+1=ma=m+n-1 ---(3)and for m+n+pth term,am+n+p=a+m+n+p-1×-1 from 3,am+n+p=a-a+p=a-a-p =-p Hence proved.

Regards.

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