Please give answer Share with your friends Share 0 Jainabbee Abid Shaikh answered this Dear student, logK1K2=∆H2.303R1T2-1T1=-∆H2.303R1T1-1T2logK1K2=-logK2K1Therefore,-logK2K1=-∆H2.303R1T1-1T2logK2K1=∆H2.303R1T1-1T2Thereofre, correct answer is 4.Regards 1 View Full Answer