Please give it's best possible solution Share with your friends Share 0 Vipra Mishra answered this Dear student Formula of electric field at axial point isE =14πεoQ×xx2+R23/2Electric field at the centre of positively charges ring due to ring 1 is zero as x= 0Electric field at the centre of positively charges ring due to ring 2 isE =14πεoQ×3 R3 R2+R23/2E =14πεoλ×2πR×3 R8R3E =116εoλ3 R As electric field due to loop 1 is zero HenceE =116εoλ3 RSo this is the net electric field at the centre of loop 1 due to charge on both loops and it is directed towards right as λ is positive for second loop.That directed from loop 2 to loop 1Regards 0 View Full Answer
