Please give me answer please help me Share with your friends Share 0 Rohit Babu answered this Dear Student,Given,hA=75m,hB=15m, m=60kga) Change in potential energy is,E=mghA-mghB=mg(hA-hB)=60×10×(75-15)=36000Jb) Given,K.E. at B=75100×E⇒K.E=75100×36000=27000J⇒12mv2=2700012×60×v2=27000v2=2700030=900v=30m/sRegards. 0 View Full Answer Roney answered this what are whole number 0
