Please give me the steps to solve these: Share with your friends Share 0 Vartika Jain answered this Dear Student, 4) (a) Cr2+6O72- + 3HN+3O2 + 5H+ → 2Cr3+ + 3N+5O3- + 4H2OHere, Cr is changing from +6 to +3 i.e. gain of electron occurs i.e. Cr is being reduced.And, N is changing from +3 to +5 i.e. loss of electrons occur i.e. N is being oxidised.Oxidising agent = Cr2O72-Reducing agent = HNO2(b) 2I+5O3- + 5N2+1O + 2H+ →I20 + 10N+2O + H2OHere, I is changing from +5 to 0 i.e. gain of electron occurs i.e. I is being reduced.And, N is changing from +1 to +2 i.e. loss of electrons occur i.e. N is being oxidised.Oxidising agent = IO3-Reducing agent = N2O(c) 2Mn+7O4- + 3Te0 + 2OH- → 4Mn+4O2 + 3Te+4O32- +H2OHere, Mn is changing from +7 to +4 i.e. gain of electron occurs i.e. Mn is being reduced.And, Te is changing from 0 to +4 i.e. loss of electrons occur i.e. Te is being oxidised.Oxidising agent = MnO4-Reducing agent = Te(d) 3Cl+7O4- + 4I- → 3Cl- 4I+5O3-Here, Cl is changing from +7 to -1 i.e. gain of electron occurs i.e. Cl is being reduced.And, I is changing from -1 to +5 i.e. loss of electrons occur i.e. I is being oxidised.Oxidising agent = ClO4-Reducing agent = I-5) (a) Here loss of electron is taking place i.e. oxidation state is changing from 0 to +1 so it is oxidation.(b) Here gain of electron is taking place i.e. oxidation state of Br s changig from 0 to -1 so reduction is taking place.(c) Oxidation state is changing from +2 to +3 i.e. loss of electrons i.e. oxidation.(d) Oxidation state is changing from +6 to +4 i.e. gain of electrons i.e. reduction. 0 View Full Answer
