please give solution fastq44

Dear Student,
Under steady state condition, there will be no current through the capacitor arm.
Equivalent resistance between A and B:
$R_{AB}=\frac{3\times 2}{3+2}=\frac{6}{5}=1.2 \Omega$
So, the current in the circuit.
$I=\frac{6}{1.2+2.8}=\frac{6}{4}=1.5 A$
Potential drop across AB:
$V_{AB}=I\times R_{AB}=1.5\times 1.2=1.8 V$
So the current through the 2ohm resistor
$i=\frac{1.8}{2}=0.9 A$
Regards