# Please give the answer for 2nd qns

The Sample space of all the possible outcomes when both players raises some fingers of one hand is given below:

If both the players raises 1 fingers of their one hand, then possible outcome: (1,1) and sum = 2

Similarly,

For TOTAL 3: (1,2)(2,1)

For TOTAL 4: (1,3)(2,2)(3,1)

For TOTAL 5: (1,4)(2,3)(3,2)(4,1)

For TOTAL 6: (1,5)(2,4)(3,3) (4,2) (5,1)

For TOTAL 7: (2,5)(3,4) (4,3) (5,2)

For TOTAL 8: (3,5) (4,4) (5,3)

For TOTAL 9 : (4,5) (5,4)

For TOTAL 10: (5,5)

So n(S) = 25

Here, maximum probability is of getting the sum of two fingers as 6.

And n(6) = 5

Hence probability of getting the sum as 6 = $\frac{5}{25}=\frac{1}{5}$

Regards

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