Dear Student,

The Sample space of all the possible outcomes when both players raises some fingers of one hand is given below:

If both the players raises 1 fingers of their one hand, then possible outcome: (1,1) and sum = 2
Similarly,
For TOTAL 3: (1,2)(2,1)
For TOTAL 4: (1,3)(2,2)(3,1)
For TOTAL 5: (1,4)(2,3)(3,2)(4,1)
For TOTAL 6: (1,5)(2,4)(3,3) (4,2) (5,1)
For TOTAL 7: (2,5)(3,4) (4,3) (5,2)
For TOTAL 8: (3,5) (4,4) (5,3)
For TOTAL 9 : (4,5) (5,4)
For TOTAL 10: (5,5)
So n(S) = 25

Here, maximum probability is of getting the sum of two fingers as 6.
And n(6) = 5
Hence probability of getting the sum as 6 =
Regards

• 1
2/10=2/10 or.o5
• 0
Hello Salma dear, the all possibilities are listed below
For TOTAL 2: (1,1)
For TOTAL 3: (1,2)(2,1)
For TOTAL 4: (1,3)(2,2)(3,1)
For TOTAL 5: (1,4)(2,3)(3,2)(4,1)
For TOTAL 6: (1,5)(2,4)(3,3) (4,2) (5,1)
For TOTAL 7: (2,5)(3,4) (4,3) (5,2)
For TOTAL 8: (3,5) (4,4) (5,3)
For TOTAL 9 : (4,5) (5,4)
For TOTAL 10: (5,5)
So n(S) = 25
And n(6) = 5
Hence max prob = 5/25 = 1/5
• 1
What are you looking for?