Please give the derivation of Magnetic Field at
1: Axial Position
2: Equatorial Position
Your query is incomplete.
Refer to the following links to find magnetic field at the axial line and equatorial line of a bar magnet.
The above diagram depicts the magnetic field at axial position
2 At the equatorial line
Let P be a point on the equatorial line of a short bar magnet where flux densitydue to the magnet is to be found out.
SN = 2l,
Magnetic flux density at p due to N-pole is
Magnetic flux density at p due to s-pole is
B1 = B2
The resultant magnetic flux density at P is
Since the bar magnet is short d >> l, l2 can be neglected as compared to d2.