please guys help with number one
Dear Student,
1) 1 mole of Calcium Carbonate(CaCO3) contains
6.02 ×1023 molecules.
Thus, mass of 1 mole of Calcium Carbonate will be
40 + 12 + 16×3 = 40 +12 + 48 = 100 g.
Regards.
1) 1 mole of Calcium Carbonate(CaCO3) contains
6.02 ×1023 molecules.
Thus, mass of 1 mole of Calcium Carbonate will be
40 + 12 + 16×3 = 40 +12 + 48 = 100 g.
Regards.