Please help me I can't solve questions of mathematical induction.I tried a lot but I always get confused in the (k+1)th step.Please tell what to do?

in this step you only have to put (k+1) instead of any integer given in the question like n.

and to elliminate your confusion, pratice..

  • 0

I have confusion only in the (k+1) step in my case practice will not do anything as practice to tab karte hain jab koi 1-2 question at least hum solve kar saken but I can't solve even a single question.

Please help

  • 0

 nitin k+1 part is to be solved tell me   cannt u even attempt ncert questions or extra book questions if those are those of ncerts u r lagging behind back up at ur earliestand i said u earlier opt for coachings . 

  • 0

 rajshree have opted for local coachings or not

  • 0

 Yes I can't even solve NCERT questions of that chapter.I also consulted the teacher he is good at teaching but he just asked me to do practice nothing else

  • 0

 I know how to solve these problems and all the necessary steps but main steps ko ulta-pulta apply kar deta hoon.Mujhe samajh nahi aata ki konsi step pehle hogi aur konsi baad me.

And still I will not opt for coaching 

  • 0

 do u know that in k+1 part u have to replace "n" of ques with k+1 and try to take common 

ncert is very easy just a job of 1and 1/2 hr at max and i believe that u can do if u ask ur teacher first and then read book 

bcz theory part of ncert is quite confusing

  • 0

u take a solved example and try 2 understand these steps

u first take n=1....i

then let p(k) is true .....ii

and then take p(k+1).....iii

in this u need to copy lhs of ii and write an extra term with "n " of last term replaced with "k+1" and in rhs simply replace n with k+1

after that take lhs of iii 

then replace entire lhs with rhs of ii + term with k+1

then try to take common  

ultimately u will get the desired rhs

  • 1

 hope u'll get that :)

  • 0

 Thanks and thumbs up but I know all these.I get confused in solving the steps of LHS for P(k+1).I 

  • 0

this is the easiest chapter after mathematical reasoning 

u post the end part till u can do perhaps then further i can help u

  • 0

Yesterday when I sat to solve those questions then I did all of them.I don't know how.I didn't do anything extra but I was able to solve all and I was unable to solve them the days before yesterday 

  • 0

congrats genius!!

  • 0

 Thanks but I'm a genius

  • 0

 Sorry its -- I'm not a genius

  • 0

 hey nitin an incident of mine my test in which i got 70 question i got upto 60 of which 40 were correct and 20 were wrong when i solved them at home i got 67 with all correct two have different answer and one unattempted 

  • 0

hi chirag what do u think the reason was ??such incidents sumtimes happen wid me too ..i m still searching the adequate explanation why it happen sum tyms..??

  • 0

 This happens to me in every maths exam.

  • 0

 my chem teacher thinks most of be to crack iit so he always scoulds me in all so when i received test he said bas aise hi karna and u will not believe 10 ques to dekht hi mujhe pata chal gaye right answers my score 92 highest score 161 my score at home 201 hahahaha difference of over 100 yaar mujhe to bas bahut gussa aaya 

  • 1

yup this prblm is quite common.??

  • 0

step 1 is usually easy, we just have to prove it is true for n=1

Step 2 is best done this way:

  • Assume it is true for n=k
  • Prove it is true for n=k+1 (we can use the n=k case as a fact.)
  • Example: is 3n−1 a multiple of 2?

    Is that true? Let us find out.


    1. Show it is true for n=1

    31−1 = 3−1 = 2

    Yes 2 is a multiple of 2. That was easy.

    31−1 is true


    2. Assume it is true for n=k

    3k−1 is true

    (Hang on! How do we know that? We don't! 
    It is an assumption ... that we treat 
    as a fact for the rest of this example)


    Now, prove that 3k+1−1 is a multiple of 2

    mathematical induction a


    3k+1 is also 3×3k

    And then split  into  and 

    And each of these are multiples of 2



  • 2×3k is a multiple of 2 (we are multiplying by 2)
  • 3k−1 is true (we said that in the assumption above)
  • So:

    3k+1−1 is true


  • 0
As you know in step 1 we put n=1 in the given question
In step 2 put n=k
In step 3 first write LHS of step 2 ,then if there is (+) in question write (+) and then put k=k+1 ,both side
Then use LHS to prove RHS
  • 1
What are you looking for?