Please help me in solving this question............ Share with your friends Share 0 Gursheen Kaur answered this Dear Student,Solution) Let ax=by=cz=k⇒ ax=k ⇒a=k1x.............(i)⇒by=k⇒b=k1y.............(ii)⇒cz=k⇒c=k1z.............(iii)As, it is given that, b2=ac ⇒ k1y2=k1x.k1z {Using i,ii and iii} ⇒ k2y=k1x+1z {In case of multiplication, when bases are same, powers are added} Now, on comparing both sides, we get, ⇒2y=1x+1z ⇒2y=z+xzx ⇒y=2zxz+x=(A) option Regards! 1 View Full Answer