Please help me with the following question

Let PQRS be a convex quadrilateral as shown in the figure. QS is joined

We know that

In a triangle, the sum of two sides is always greater than the third side

Therefore,

In ΔPQS

PQ + QS > PS          (1)

Again in ΔQRS

QR + RS > QS         (2)

Adding both the inequalities

PQ + QS + QR + RS > PS + QR

or, PQ + QR + RS > PS                   (Hence Proved)
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