Please help me with this one also Share with your friends Share 0 Atul Shaw answered this Dear student,σ2=∑i xi2n-∑i xin2σ2≥0∑i xi2n-∑i xin2≥0∑i xi2n-∑i xi2n2≥0∑i xi2n≥∑i xi2n2As n and n2are positive thus they can be cross multiplied with inequality change n2×n(n2+2n+1)n≥∑i xi2For max. value of ∑i xi, so ∑i xi2 should also be maxm.for maxm. value, equality should be hold.n2(n2+2n+1)=∑i xi2n(n+1)2=∑i xi2∑i xi=n(n+1)=n2+na. (a+b)2=a2+b2+2abRegards 0 View Full Answer