Please help me with this question experts please ............ Share with your friends Share 0 Anshu Agrawal answered this Dear student, For an internal point, r<R Binternal =μ0(0)2πr=0 For a point on the pipe, r=R B=μ0(I)2πr For an external point, r<R Bextemal =μ0(I)2πr Regards 1 View Full Answer
