Please help to solve this

Dear student,
kindly find the solution below

if the under root is only on p that if it is p  instead of the whole term then denominator will become zero.therefore,Making an assumption in the question as given below,If x=p+2q+p-2qp+2q-p-2q    x=p+2q+p-2qp+2q-p-2q×p+2q+p-2qp+2q+p-2q----(Rationalising)    x=p+2q+p-2q2p+2q2-p-2q2     x=p+2q)2+(p-2q2+2p+2qp-2qp+2q2-p-2q2 x=p+2q+p-2q+2p2-4q2p+2q-p+2q  x=2p+2p2-4q24q=p+p2-4q22q   2qx=p+p2-4q22qx-p=p2-4q2squaring2qx-p2=p2-4q224q2x2+p2-2×2qx×p=p2-4q24q2x2-4qxp=-4q24q2x2-4qpx+4q2=0dividing by 4qqx2-px+q=0Hence Proved.

Regards
​​​​​ 

 

  • 0
What are you looking for?