Please help to solve this Share with your friends Share 0 Roopam Pandey answered this Dear student, kindly find the solution below if the under root is only on p that if it is p instead of the whole term then denominator will become zero.therefore,Making an assumption in the question as given below,If x=p+2q+p-2qp+2q-p-2q x=p+2q+p-2qp+2q-p-2q×p+2q+p-2qp+2q+p-2q----(Rationalising) x=p+2q+p-2q2p+2q2-p-2q2 x=p+2q)2+(p-2q2+2p+2qp-2qp+2q2-p-2q2 x=p+2q+p-2q+2p2-4q2p+2q-p+2q x=2p+2p2-4q24q=p+p2-4q22q 2qx=p+p2-4q22qx-p=p2-4q2squaring2qx-p2=p2-4q224q2x2+p2-2×2qx×p=p2-4q24q2x2-4qxp=-4q24q2x2-4qpx+4q2=0dividing by 4qqx2-px+q=0Hence Proved. Regards 0 View Full Answer