please how this answer is come
Dear Student,
According to the IUPAC name given, COOH should be present instead of CO.
If it is COOH, then the functional group present will be carboxylic acid i.e. -COOH. Therefore, it will get the highest priority. Therefore, the C attached to COOH will be numbered 1.
Now, according to the lowest locant rule, numbering will be done in the clockwise manner in order to give substituents minumum locant. Therefore, Cl will be numbered 2 and the other substituent which is a substituted benzoyloxy will be numbered 4.
Now, the IUPAC of the substituent will be 4-chlorobenzoyloxy
Therefore, IUPAC of the given compound will be 2-chloro-4-[4-chlorobenzoyloxy] benzoic acid.
According to the IUPAC name given, COOH should be present instead of CO.
If it is COOH, then the functional group present will be carboxylic acid i.e. -COOH. Therefore, it will get the highest priority. Therefore, the C attached to COOH will be numbered 1.
Now, according to the lowest locant rule, numbering will be done in the clockwise manner in order to give substituents minumum locant. Therefore, Cl will be numbered 2 and the other substituent which is a substituted benzoyloxy will be numbered 4.
Now, the IUPAC of the substituent will be 4-chlorobenzoyloxy
Therefore, IUPAC of the given compound will be 2-chloro-4-[4-chlorobenzoyloxy] benzoic acid.