Please make me understand this
to prove sqrt( ( 1+cos(x)) / ( 1 - cos(x) ) ) = cosec(x) + cot(x)
LHS
( 1+cos(x) ) / ( 1 - cos(x) )
= [ ( 1+cos(x) )( 1+cos(x) )] / [( 1 - cos(x) ) ( 1+cos(x) ) ] # multiply numerator and denominator by ( 1+cos(x) )
= ( 1+cos(x) )^2/(1 -cos^2(x)
= ( 1+cos(x) )^2/sin^2(x)
thus
( 1+cos(x) ) / ( 1 - cos(x) ) = ( 1+cos(x) )^2/sin^2(x)
sqrt( ( 1+cos(x) ) / ( 1 - cos(x) ) = sqrt ( ( 1+cos(x) )^2/sin^2(x) ) = (1 + cos(x) )/sin(x) = cosec(x) + cot(x)
LHS
( 1+cos(x) ) / ( 1 - cos(x) )
= [ ( 1+cos(x) )( 1+cos(x) )] / [( 1 - cos(x) ) ( 1+cos(x) ) ] # multiply numerator and denominator by ( 1+cos(x) )
= ( 1+cos(x) )^2/(1 -cos^2(x)
= ( 1+cos(x) )^2/sin^2(x)
thus
( 1+cos(x) ) / ( 1 - cos(x) ) = ( 1+cos(x) )^2/sin^2(x)
sqrt( ( 1+cos(x) ) / ( 1 - cos(x) ) = sqrt ( ( 1+cos(x) )^2/sin^2(x) ) = (1 + cos(x) )/sin(x) = cosec(x) + cot(x)