Please provide a solution of this questio as Ihave stuck to eliminate ex if y=ex.tan-1x then prove that (1+x2)d2y/dx2 -2(1-x+x2)dy/dx +(1-x2)y=0 Share with your friends Share 2 Priyanka Kedia answered this Recheck your question. y=extan-1xDifferentiating w.r.t. x on both sides, we have,dydx=ddxextan-1x =exddxtan-1x+tan-1xddxex =ex11+x2+tan-1xex =ex11+x2+tan-1x⇒dydx=ex11+x2+tan-1xAgain differentiating w.r.t. x on both sides, we have,d2ydx2=ddxex11+x2+tan-1x d2ydx2=ddxex11+x2+tan-1x =exddx11+x2+tan-1x+11+x2+tan-1xddxex =ex-2x1+x22+11+x2+11+x2+tan-1xex =ex-2x+1+x21+x22+11+x2+tan-1xex =ex-2x+1+x21+x22+11+x2+tan-1x =ex-2x+1+x2+1+x21+x22+tan-1x =ex-2x+2+2x21+x22+tan-1x⇒d2ydx2=ex-2x+2+2x21+x22+tan-1x Now,L.H.S.=1+x2d2ydx2-21-x+x2dydx+1-x2y =1+x2ex-2x+2+2x21+x22+tan-1x-21-x+x2ex11+x2+tan-1x+1-x2extan-1x =1+x2ex-2x+2+2x21+x22+1+x2extan-1x-21-x+x2ex11+x2-21-x+x2extan-1x+1-x2extan-1x =21-x+x2ex11+x2+1+x2extan-1x-21-x+x2ex11+x2-21-x+x2extan-1x+1-x2extan-1x =extan-1x1+x2-21-x+x2+1-x2 =extan-1x2x-2x2 =R.H.S. Hence Proved. -19 View Full Answer