Please provide a solution of this questio as Ihave stuck to eliminate ex

if y=ex.tan-1x then prove that (1+x2)d2y/dx2 -2(1-x+x2)dy/dx +(1-x2)y=0

Recheck your question.
y=extan-1xDifferentiating w.r.t. x on both sides, we have,dydx=ddxextan-1x       =exddxtan-1x+tan-1xddxex       =ex11+x2+tan-1xex       =ex11+x2+tan-1xdydx=ex11+x2+tan-1xAgain differentiating w.r.t. x on both sides, we have,d2ydx2=ddxex11+x2+tan-1x
d2ydx2=ddxex11+x2+tan-1x        =exddx11+x2+tan-1x+11+x2+tan-1xddxex        =ex-2x1+x22+11+x2+11+x2+tan-1xex        =ex-2x+1+x21+x22+11+x2+tan-1xex        =ex-2x+1+x21+x22+11+x2+tan-1x        =ex-2x+1+x2+1+x21+x22+tan-1x        =ex-2x+2+2x21+x22+tan-1xd2ydx2=ex-2x+2+2x21+x22+tan-1x
Now,L.H.S.=1+x2d2ydx2-21-x+x2dydx+1-x2y            =1+x2ex-2x+2+2x21+x22+tan-1x-21-x+x2ex11+x2+tan-1x+1-x2extan-1x            =1+x2ex-2x+2+2x21+x22+1+x2extan-1x-21-x+x2ex11+x2-21-x+x2extan-1x+1-x2extan-1x            =21-x+x2ex11+x2+1+x2extan-1x-21-x+x2ex11+x2-21-x+x2extan-1x+1-x2extan-1x            =extan-1x1+x2-21-x+x2+1-x2            =extan-1x2x-2x2            =R.H.S.
Hence Proved.

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