Please provide all the formula related to 1st and 2nd chapter of physics class 12 "Electric charges and fields" and Electrostatic potential and capacitance". Do not say that refer the study material or revision notes.

Dear Student,

Please find below the solution to the asked query:

Here i am providing some of the important formulae, but i strongly suggest you, please study from books. Because, in order to solve the problems, you have to know the interrelation between the topics. If you try to remember the formulae, you will not be able to apply for the problems. Some of the topics i am entering slide images, because, this is too lengthy question. Typing is too difficult. If you want to know as typed, Please ask topic by topic.

Electric Charge:

Coulumb's Law:
  • Electric force between two point charges :      F12=14πε0Kq1q2r122r12^=-F21
where K = 1 for free space​, 14πε0K=9×109 N m2 C-2
  • Coulomb's law agrees with Newton's third law.
  • Force on charge q1 due to remaining charges q2, q3, q4, ... qn in the region is ; 
It is a vector sum of all the forces acting on point charge q1.​

Electric Field:
  • Electric flux through a plane surface area S held in a uniform electric field​
ϕE=E.S=ES cos θ
  • According to Gauss's law, electric flux through a closed surface S is equal to 1ε0 times charge enclosed.
  • Electric field due to a long straight wire of uniform linear charge density λ is E=λ2πε0r
  • Electric field due to an infinite plane sheet of uniform surface charge density σ is E=σ2ε0
  • Electric field due to two equally and oppositely charged parallel plates is 
E=0 for outside points; E=σε0for inside points
  • Electric field due to a thin spherical shell of charge density ρ and radius R is
E=14πε0qr2 for r>RE=14πε0qrR3 for r<RE=14πε0qR2 for r=RWhere,q=43πR3ρ

Electric Potential:

Potential of charge distributions:

Electrostatic Potential Energy:

Electric Dipole:

Dielectrics and Polarisation:

Capacitors and Capacitance:

Different types of Capacitors:

Combination of Capacitors:



Hope this information will clear your doubts about the topic.

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