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Please slove question 13

​Q13. In a circle of radius 5 cm, AB and AC are two chords such that AB = AC = 6 cm. The length of the chord BC is 

       (A) 9.6 cm.                                              (B) 9.8 cm.

       (C) 10 cm.                                               (D) 11 cm.
 

Kindly, refer to the below link for similar query,
https://www.meritnation.com/ask-answer/question/in-a-circle-of-radius-5cm-ab-and-ac-are-two-chords-such-tha/circles/1844648

Regards.

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9. 8
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observe triangle OAC, AC =6, OF perpendicular to AC, therefore area of triangle OAC = 1/2 * AC * OF, =1/2 * 6 * 4 =12
Now CD is perpendicular to OA, therefore Area of triangle OAC = 1/2 * OA * CD=12= 1/2 * 5 * CD, therefore CD= 24/5 = 4.8
BC = BD + CD, BD=CD therefore BC= 4.8+4.8= 9.6
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