Please solve:

153. If sec  α  and cosec  α are the roots of the equation x2 -ax +b =0, then

(a) a2 = b(b -2)                   (b) a2 =b (b +2)  ​
(c) a+ b=2b                    (d) none of these

Dear Student,
Please find below the solution to the asked query:

x2-ax+b=0Roots are secα and cosecαProduct of roots=bsecα.cosecα=b1cosα1sinα=bsinα.cosα=1b...iSum of roots=asecα +cosecα=a1cosα+1sinα=asinα+cosαsinα.cosα=asinα+cosα=asinα.cosαsinα+cosα=ab  Use iSquare both sidessinα+cosα2=a2b2sin2α+cos2α+2sinα.cosα=a2b21+2b=a2b2b2+b22b=a2a2=b2+2ba2=bb+2...Optionb

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