Please solve and answer with detail.


 

Dear student
log3+223-22=log3+223-2212=12log3+223-22     logaxb=blogax=12log3+22123-22=2×12log3+223-22      logabx=1blogax=log3+223-22=--log3+223-22=-log3+2213-22       logb1y=-logby=-log3+2213-22×3+223+22=-log3+223+2232-222=-log3+223+229-8=-log3+223+22       logaa=1=-1
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