PLEASE SOLVE AND GIVE CORRECT ANSWER
Question 76 of 90
0 π / 2 d x 1 + tan 3 x is :
1. 0
2. 1
3. π /2
4. π /4

Let I = 0π/2dx1 + tan3x    I= 0π/2dx1 + sin3xcos3xI = 0π/2cos3xcos3x + sin3x dx    .....1I = 0π/2cos3π2-xcos3π2 - x + sin3π2-xdxI = 0π/2sin3xsin3x + cos3xdx     .....2Adding 1 and 2, we get    2I = 0π/2sin3x + cos3xsin3x + cos3x dx2I = 0π/2 dx2I = x0π/22I = π2I = π4

  • 0
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