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Question 85 of 90
If I = - 1 1 x 2 + sin   x 1 + x 2 d x then
1. 0
2. 2
3. pi/2
4. 2-pi/2

Dear Student,
Please find below the solution to the asked query:

I=-11 x2+sinx1+x2.dx=-11 x21+x2.dx+-11sinx1+x2.dxNow x21+x2 is even function and sinx1+x2 is odd functionWe know that-aafx.dx=0if fx is odd20afx.dxif fx is even...iHenceI=201 x21+x2.dx+0=2011+x21+x2-11+x2dx=2011-11+x2dx=2 x-tan-1x01=2 1-tan-11-0=21-π4=2-π2 Answer

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