Dear Student, given,length of the rod,l=6m=600 cmdiameter of the rod,d=20mm=2 cmincrease in temperature,t=80°Cyoung's modulus,Y=1 2×1011N/m2=1 2×10-5 kg/cm2coefficient of linear expansion,α=2×10-5/°Cwhen the ends do not yieldlet σ1=stress in the rodusing the relation,σ=αtYσ1=2×10-5×80×1 2×10-5=192×10-10 kg/cm2 option(4) is correct Hope this information will clear your doubts about topic If you have any more doubts just ask here on the forum and our experts will try to help you out as soon as possible Regards

Please solve it,, ..

Dear Student,

g i v e n, l e n g t h o f t h e r o d, l = 6 m = 600 c m d i a m e t e r o f t h e r o d, d = 20 m m = 2 c m i n c r e a s e i n t e m p e r a t u r e, t = 80 ° C y o u n g' s m o d u l u s, Y = 1.2 \times 10^{11} N / m^{2} = 1.2 \times 10^{- 5} k g / c m^{2} c o e f f i c i e n t o f l i n e a r e x p a n s i o n, α = 2 \times 10^{- 5} / ° C w h e n t h e e n d s d o n o t y i e l d l e t σ_{1} = s t r e s s i n t h e r o d u \sin g t h e r e l a t i o n, σ = α t Y σ_{1} = (2 \times 10^{- 5}) \times (80) \times (1.2 \times 10^{- 5}) = 192 \times 10^{- 10} k g / c m^{2}

option(4) is correct.

Hope this information will clear your doubts about topic.

If you have any more doubts just ask here on the forum and our experts will try to help you out as soon as possible.

Regards

View Full Answer