We know ABC is a right triangle
Therefore, AC²=AB²+BC²... (using pythagoras theorem)
AC²=8²+6²
=100
AC=10cm
Now,
Since AFD,ADC and BEC are semicircles
Therefore Area o is equal to 1/2π radius²
Radius of AFB=8/2=4,
radius of ADC=10/2=5
and radius of BEC= 6/2=3
Area of AFB=1/2×22/7×4²
=176/7cm²...(1)
Area of ADC=1/2×22/7×5²
=275/7cm²...(2)
Area of BEC=1/2×22/7×3²
=99/7cm²...(3)
Area of triangle ABC =1/2×Base×Height
=1/2×6×8=24cm²
Adding 1,2,3and4we get
102.571(approx)
