Dear student, Step 1: Draw a line AB of line segment 7 cm Step 2: Putting the protactor at point A mark a point where it makes an angle 6712 =62 5° Step 3: Similarly put a protactor ar point B and mark a point where it makes 15° Step 3: Mark the point C where it coincides with the line of 62 5° Hence ∆ABC is a required ∆ Regards

Please solve no.14.

Please solve no.14. 14. Draw AABC with AB=7cm, LA = 6710, LB = 150 without using a protractor.

Dear student,

S t e p 1 : D r a w a l i n e A B o f l i n e s e g m e n t 7 c m . S t e p 2 : P u t t i n g t h e p r o t a c t o r a t p o i n t A m a r k a p o i n t w h e r e i t m a k e s a n a n g l e 67 \frac{1}{2} = 62.5 ° . S t e p 3 : S i m i l a r l y p u t a p r o t a c t o r a r p o i n t B a n d m a r k a p o i n t w h e r e i t m a k e s 15 ° . S t e p 3 : M a r k t h e p o i n t C w h e r e i t c o i n c i d e s w i t h t h e l i n e o f 62.5 ° . H e n c e ∆ A B C i s a r e q u i r e d ∆ .

Regards

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Please solve no.14. Please solve no.14. 14. Draw AABC with AB=7cm, LA = 6710, LB = 150 without using a protractor.

Please solve no.14.

Please solve no.14. 14. Draw AABC with AB=7cm, LA = 6710, LB = 150 without using a protractor.