Please solve Q. 0.05 M ammonium hydroxide solution is dissolved in 0.001 M ammonium chloride solution . What will be the O H - ion concentration of this solution : K b N H 4 O H = 1 . 8 × 10 - 5 1 3 . 0 × 10 - 3 2 9 . 0 × 10 - 4 3 9 . 0 × 10 - 3 4 3 . 0 × 10 - 4 Share with your friends Share 14 Vartika Jain answered this Dear Student, According to Henderson-Haselbach equation, pOH=pKb- log[Base][Salt]pOH=pKb- log[NHOHl][NH4Cl]or, pOH= -log (1.8×10-5)-log(0.05)(0.001) =-[log(1.8)-5log10]-log (50) =-0.255+5-1.69 =4.74-1.69 =3.05or, -log [OH-]=3.05or. [OH-] =10-3.05 = 8.9×10-4 ≈ 9×10-4Hence, correct answer is (2) 21 View Full Answer