Please solve q18 Share with your friends Share 0 Ved Prakash Lakhera answered this Let us think the situation when the bead is hsa slided distance x, on leleasing the the particle of mass m.THe length of string is L. When particle was released, the length of the string at the original point from the point bead slided= (L -x).In this position the angle made by the string with horizontal = θ.The right angled tringle so formed, has base=(L-x) and hypotenuse=L.Therefore cosθ=L-xL OR cosθ=1-xL OR x = L 1 -cosθ .Therefore option (a) is the correct answer.. -149 View Full Answer