Please solve question 15 .

​​​​15. ​​​A system of two capacitors is shown in the figure.

If V_P − V_Q = +20 V, then
(A) If switch S₂ is closed potential difference between plate A and plate B is 15 volt.
(B) If all switches are closed, Q_A = $-\frac{20}{6}\mathrm{\mu C}$ and Q_C = $\frac{10}{3}\mathrm{\mu C}$
(C) If all switches are closed V_P − V_Q = $\frac{10}{6}\mathrm{volt}$
(D) If all switches are closed, energy loss in the circuit is $\frac{625}{3}\mathrm{\mu J}.$