Please solve question 16

Dear student, Let the number be 2 m + 1 where m can be any integer . {(2 m + 1)}^{2} = 4 m^{2} + 4 m + 1 [{(a + b)}^{2} = a^{2} + 2 ab + b^{2}] So, the term 4 m^{2} + 4 m + 1 = 2 \times (2 m^{2} + 2 m) + 1 So, the whole term is not completey divisible by 2 and thus it is also a odd number . And hence it is proved that square of an odd integer is odd . Regards

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