Please solve question no. 10 (ii)
Dear student
I assume you want to determine the value of c so that the limit tends to 4.
First of all, we need to admit that c is finite and <>0, else it makes no sense.
Then perform these steps:
Lim (x→∞) [(x-c+2c)/(x-c)]^x = Lim (x→∞) [1+2c/(x-c)]^x
Now let: 2c/(x-c) = 1/t ==> x = c(2t+1), with t still approaching infinity. The limit becomes:
Lim (t→∞) [1+1/t]^c(2t+1) = Lim (t→∞) [(1+1/t)*(1+1/t)^2t]^c
We know that (for c finite)
Lim (t→∞) (1+1/t)^c = 1 and
Lim (t→∞) [(1+1/t)^2t]^c = Lim (t→∞) [(1+1/t)^t]^2c = e^(2c)
Therefore we need to have:
e^(2c) = 4
2c = ln4
c = ln4/2
Regards
I assume you want to determine the value of c so that the limit tends to 4.
First of all, we need to admit that c is finite and <>0, else it makes no sense.
Then perform these steps:
Lim (x→∞) [(x-c+2c)/(x-c)]^x = Lim (x→∞) [1+2c/(x-c)]^x
Now let: 2c/(x-c) = 1/t ==> x = c(2t+1), with t still approaching infinity. The limit becomes:
Lim (t→∞) [1+1/t]^c(2t+1) = Lim (t→∞) [(1+1/t)*(1+1/t)^2t]^c
We know that (for c finite)
Lim (t→∞) (1+1/t)^c = 1 and
Lim (t→∞) [(1+1/t)^2t]^c = Lim (t→∞) [(1+1/t)^t]^2c = e^(2c)
Therefore we need to have:
e^(2c) = 4
2c = ln4
c = ln4/2
Regards