Please solve question no 13 and 14 on a page

Dear Student,


$$\begin{gathered} \mathrm{Let} \mathrm{E} \mathrm{be} \mathrm{the} \mathrm{effort} \mathrm{applied} \mathrm{on} \mathrm{the} \mathrm{smaller} \mathrm{piston} \mathrm{A} \mathrm{and} \mathrm{L} \mathrm{be} \mathrm{the} \mathrm{load} \mathrm{on} \mathrm{the} \mathrm{larger} \mathrm{piston} \mathrm{B}. \\ \mathrm{Area} \mathrm{of} \mathrm{cross} \mathrm{section} \mathrm{of} \mathrm{piston} \mathrm{A}=8 {\mathrm{cm}}^2 \\ \mathrm{Area} \mathrm{of} \mathrm{cross} \mathrm{section} \mathrm{of} \mathrm{piston} \mathrm{B}=320 {\mathrm{cm}}^2 \\ \left(1\right) \mathrm{According} \mathrm{to} \mathrm{pascal}\text{'}\mathrm{s} \mathrm{law}, \mathrm{the} \mathrm{pressure} \mathrm{acting} \mathrm{on} \mathrm{piston} \mathrm{A} \mathrm{in} \mathrm{the} \mathrm{downward} \mathrm{direction}, \\ {\mathrm{P}}_{\mathrm{A}}=\frac{\mathrm{Thrust}}{\mathrm{Area}} \\ {\mathrm{P}}_{\mathrm{A}}=\frac{\mathrm{E}}{8} \mathrm{N}/{\mathrm{cm}}^2 \\ \left(2\right) \mathrm{The} \mathrm{pressure} \mathrm{acting} \mathrm{on} \mathrm{B} \mathrm{is} \mathrm{equal} \mathrm{to} \mathrm{the} \mathrm{Pressure} \mathrm{acting} \mathrm{on} \mathrm{A}, \\ {\mathrm{P}}_{\mathrm{B}}=\frac{\mathrm{E}}{8} \mathrm{N}/{\mathrm{cm}}^2 ........... \left[\mathrm{because} \mathrm{both} \mathrm{the} \mathrm{piston} \mathrm{are} \mathrm{at} \mathrm{same} \mathrm{height}\right] \\ \left(3\right) \mathrm{Thrust} \mathrm{acting} \mathrm{on} \mathrm{piston} \mathrm{B} \mathrm{in} \mathrm{upward} \mathrm{direction}, \\ {\mathrm{T}}_{\mathrm{B}}={\mathrm{P}}_{\mathrm{B}}\times \mathrm{Area} \mathrm{of} \mathrm{B} \\ {\mathrm{T}}_{\mathrm{B}}=\frac{\mathrm{E}}{8}\times 320=40\mathrm{E} \\ \mathrm{If} \mathrm{E} \mathrm{is} \mathrm{known} \mathrm{then} \mathrm{you} \mathrm{can} \mathrm{calculate} \mathrm{all} \mathrm{the} \mathrm{values}. \end{gathered}$$
Now since E= 4kg
1. P_A=  4/8= 0.5 N/cm²
2. P_B = 4/8= 0.5 N/cm²
3. T_B = 40X4= 160Kgf

I have answered your first question. Kindly ask the other question in a separate thread.

Thanks and regards.