Please solve question no. 2

\frac{4 \sqrt{3} + \sqrt{2}}{2 \sqrt{3} - 3 \sqrt{2}} = \frac{4 \sqrt{3} + \sqrt{2}}{2 \sqrt{3} - 3 \sqrt{2}} \times \frac{2 \sqrt{3} + 3 \sqrt{2}}{2 \sqrt{3} + 3 \sqrt{2}} = \frac{(4 \sqrt{3} + \sqrt{2}) (2 \sqrt{3} + 3 \sqrt{2})}{(2 \sqrt{3} - 3 \sqrt{2}) (2 \sqrt{3} + 3 \sqrt{2})} = \frac{24 + 12 \sqrt{6} + 2 \sqrt{6} + 6}{{(2 \sqrt{3})}^{2} - {(3 \sqrt{2})}^{2}} = \frac{30 + 14 \sqrt{6}}{12 - 18} = \frac{30 + 14 \sqrt{6}}{- 6} = \frac{2 [15 + 7 \sqrt{6}]}{- 6} = - \frac{(15 + 7 \sqrt{6})}{3} Using : (a + b) (a - b) = a^{2} - b^{2}

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