Please solve:
Question no.26

Dear student

\frac{2 \cos^{2} 90 ° + 4 \cos^{2} 45 ° + \tan^{2} 60 ° + 3 {cosec}^{2} 60 °}{3 \sec 60 ° - \frac{7}{2} \sec^{2} 45 ° + 2 cosec 30 °} = \frac{2 {(0)}^{2} + 4 {(\frac{1}{\sqrt{2}})}^{2} + {(\sqrt{3})}^{2} + 3 {(\frac{2}{\sqrt{3}})}^{2}}{3 (2) - \frac{7}{2} {(\sqrt{2})}^{2} + 2 (2)} = \frac{0 + 2 + 3 + 4}{6 - 7 + 4} = \frac{9}{3} = 3

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