Please solve question no.3.

Dear student, Given: D,E,F are the mid points of AB,BC,CA To Prove: DE = EF Proof: AB = AC (isosceles triangle)            ∠B = ∠C (angle opp to equal sides)           ¹/₂ AB = ¹/₂ AC           so,DB = CF           In ΔADF and ΔCEF               DB = CF (proved above)               BE = CE (E is the mid point of BC)              ∠B = ∠C (proved above)           ∴ ΔADF = ΔCEF (SAS)                DE = FE (CPCT) Hence, Proved Regards.

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