Please solve question no.3.
Dear student, Given: D,E,F are the mid points of AB,BC,CA To Prove: DE = EF Proof: AB = AC (isosceles triangle) ∠B = ∠C (angle opp to equal sides) ¹/₂ AB = ¹/₂ AC so,DB = CF In ΔADF and ΔCEF DB = CF (proved above) BE = CE (E is the mid point of BC) ∠B = ∠C (proved above) ∴ ΔADF = ΔCEF (SAS) DE = FE (CPCT) Hence, Proved Regards.