Please solve question no.4.

Dear Student

See Ans 4.

Q 1 S p e e d o f l i g h t i n a i r = 3 \times 10^{8} m s^{- 1} μ = 1.5 μ = \frac{c}{v} v e l o c i t y o f l i g h t i n g l a s s = 3 \times 10^{8} / 1.5 = 2 \times 10^{8} m s^{- 1} Q 2 s p e e d o f l i g h t i n d i a m o n d = 12500 K m / s e c = 12500000 m s^{- 1} R e f r a c t i v e i n d e x = c / v = \frac{3 \times 10^{8}}{125 \times 10^{6}} = 2.4 Q 3 μ_{12} = \frac{1}{μ_{21}} r e f r a c t i v e i n d e x o f a i r w r t t o g l a s s = \frac{1}{r e f r a c t i v e i n d e x o f g l a s s w r t t o a i r} = 3 / 4 = 0.75 Q 4 μ = \frac{c}{v} μ = \frac{λ_{a i r}}{λ_{g l a s s}} λ g l a s s = 5400 \times 2 / 3 = 3600 A H o p e t h i s i n f o r m a t i o n w i l l c l e a r y o u r d o u b t s a b o u t t o p i c . I f y o u h a v e a n y m o r e d o u b t s j u s t a s k h e r e o n t h e f o r u m a n d o u r e x p e r t s w i l l t r y t o h e l p y o u o u t a s s o o n a s p o s s i b l e . R e g a r d s