Please solve question number 2 in the following

Dear Student.

$$\begin{gathered} we have: \frac{2}{5}\times \left(\frac{-3}{7}\right)-\frac{1}{14}-\frac{3}{7}\times \frac{3}{5} \\ =\frac{1}{7}\left\{\frac{2}{5}\times \left(-3\right)-\frac{1}{2}-3\times \frac{3}{5}\right\} \\ =\frac{1}{7}\left\{\frac{-6}{5}-\frac{9}{5}-\frac{1}{2}\right\}=\frac{1}{7}\left\{\frac{-15}{5}-\frac{1}{2}\right\} \\ =\frac{1}{7}\left\{-3-\frac{1}{2}\right\}=\frac{1}{7}\left\{\frac{-6-1}{2}\right\} \\ =\frac{1}{7}\times \frac{\left(-7\right)}{2} \\ =-\frac{1}{2} \end{gathered}$$

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