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Please solve question number 26,,

D e a r s t u d e n t, \frac{x^{3} + 4 x y^{2}}{4 x^{2} y + y^{3}} = \frac{15}{16} D i v i d e b y x^{3} i n N' r a n d D' r \frac{\frac{x^{3}}{x^{3}} + \frac{4 x y^{2}}{x^{3}}}{\frac{4 x^{2} y}{x^{3}} + \frac{y^{3}}{x^{3}}} = \frac{15}{16} L e t \frac{y}{x} = t \Rightarrow \frac{1 + 4 (\frac{y}{x})}{\frac{4 y}{x} + {(\frac{y}{x})}^{3}} = \frac{15}{16} \Rightarrow \frac{1 + 4 t^{2}}{4 t + t^{3}} = \frac{15}{16} \Rightarrow 16 + 64 t^{2} = 60 t + 15 t^{3} \Rightarrow 15 t^{3} - 64 t^{2} + 60 t - 16 = 0 \Rightarrow 15 t^{3} + 60 t - 64 t^{2} - 16 = 0 F r o m h e r e, w e n e e d c o n c e p t o f h i g h e r c l a s s e s . R e g a r d s

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