Please solve the 13 th problem.
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Dear Student, Here three 1 ohm resistors are in series so their equivalent is 3 ohm. Now three 2 ohm resistors are also in series combination so their equivalent is also 6 ohm. Now the equivalent resistance of the loop is = parallel combination of 3 ohm,2 ohm and 6 ohm resistors= 1 ohm .Now the two 1 ohm resistors in the left and right side are in series combination with the 1 ohm . Therefore the equivalent resistance of the circuit is= 1+1+1 = 3 ohm. Regards