Please solve the 25(ii) number.
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Q.25. A particular resistance wire has a resistance of 3.0 ohm per metre. Find :
(a) The total resistance of three lengths of this wire each 1.5 m long, joined in parallel.
(b) The potential difference of the battery which gives a current of 2.0 A in each of the 1.5 m length when connected in parallel to the battery (assume that the resistance of battery is negligible).

Dear student,1m=3ohm1.5m=3+1.5=4.5ohma) 1Rp=14.5+14.5+14.5Rp=1.5ohmb) V=irV=1.5×(2+2+2)=9VRegards

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